(X^2+3x+2)(4)=24x-1

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Solution for (X^2+3x+2)(4)=24x-1 equation: 



(X^2+3X+2)(4)=24X-1

We move all terms to the left:

(X^2+3X+2)(4)-(24X-1)=0

We multiply parentheses

4X^2+12X-(24X-1)+8=0

We get rid of parentheses

4X^2+12X-24X+1+8=0

We add all the numbers together, and all the variables

4X^2-12X+9=0

a = 4; b = -12; c = +9;
Δ = b2-4ac
Δ = -122-4·4·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{12}{8}=1+1/2$

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